Question
Answer
$$\dfrac{(x+h)^3-x^2}{h}=\dfrac{x^3+3hx^2+3h^2x+h^3-x^2}{h}$$
Explanation
| $$ \begin{aligned}\frac{(x+h)^3-x^2}{h}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x^3+3hx^2+3h^2x+h^3-x^2}{h}\end{aligned} $$ | |
| ① | Find $ \left(x+h\right)^3 $ using formula $$ (A + B) = A^3 + 3A^2B + 3AB^2 + B^3 $$where $ A = x $ and $ B = h $. $$ \left(x+h\right)^3 = x^3+3 \cdot x^2 \cdot h + 3 \cdot x \cdot h^2+h^3 = x^3+3hx^2+3h^2x+h^3 $$ |
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