Question
Find roots of polynomial $$ p(x) = y^2+6y+7 $$
Answer
The roots of polynomial $ p(y) $ are:
$$ \begin{aligned}y_1 &= -1.5858\\[1 em]y_2 &= -4.4142 \end{aligned} $$Explanation
The solutions of $ y^2+6y+7 = 0 $ are: $ y = -3-\sqrt{ 2 } ~ \text{and} ~ y = -3+\sqrt{ 2 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator