The roots of polynomial $ p(y) $ are:
$$ \begin{aligned}y_1 &= 0\\[1 em]y_2 &= -25 \end{aligned} $$Step 1:
Factor out $ \color{blue}{ y }$ from $ y^2+25y $ and solve two separate equations:
$$ \begin{aligned} y^2+25y & = 0\\[1 em] \color{blue}{ y }\cdot ( y+25 ) & = 0 \\[1 em] \color{blue}{ y = 0} ~~ \text{or} ~~ y+25 & = 0 \end{aligned} $$One solution is $ \color{blue}{ y = 0 } $. Use second equation to find the remaining roots.
Step 2:
To find the second zero, solve equation $ y+25 = 0 $
$$ \begin{aligned} y+25 & = 0 \\[1 em] y & = -25 \end{aligned} $$