Question
Find roots of polynomial $$ p(x) = y^2+20y+77 $$
Answer
The roots of polynomial $ p(y) $ are:
$$ \begin{aligned}y_1 &= -5.2042\\[1 em]y_2 &= -14.7958 \end{aligned} $$Explanation
The solutions of $ y^2+20y+77 = 0 $ are: $ y = -10-\sqrt{ 23 } ~ \text{and} ~ y = -10+\sqrt{ 23 }$.
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