Question
Find roots of polynomial $$ p(x) = x^2+6x-120 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 8.3578\\[1 em]x_2 &= -14.3578 \end{aligned} $$Explanation
The solutions of $ x^2+6x-120 = 0 $ are: $ x = -3-\sqrt{ 129 } ~ \text{and} ~ x = -3+\sqrt{ 129 }$.
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