Question
Find roots of polynomial $$ p(x) = x^2+36x-162 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 4.0454\\[1 em]x_2 &= -40.0454 \end{aligned} $$Explanation
The solutions of $ x^2+36x-162 = 0 $ are: $ x = -18-9 \sqrt{ 6 } ~ \text{and} ~ x = -18+9 \sqrt{ 6 }$.
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