Question
Find roots of polynomial $$ p(x) = x^2+350x-1375 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 3.8854\\[1 em]x_2 &= -353.8854 \end{aligned} $$Explanation
The solutions of $ x^2+350x-1375 = 0 $ are: $ x = -175-80 \sqrt{ 5 } ~ \text{and} ~ x = -175+80 \sqrt{ 5 }$.
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