Question
Find roots of polynomial $$ p(x) = x^2+32x+36 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -1.1676\\[1 em]x_2 &= -30.8324 \end{aligned} $$Explanation
The solutions of $ x^2+32x+36 = 0 $ are: $ x = -16-2 \sqrt{ 55 } ~ \text{and} ~ x = -16+2 \sqrt{ 55 }$.
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