Question
Find roots of polynomial $$ p(x) = x^2+30x+40 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -1.3985\\[1 em]x_2 &= -28.6015 \end{aligned} $$Explanation
The solutions of $ x^2+30x+40 = 0 $ are: $ x = -15-\sqrt{ 185 } ~ \text{and} ~ x = -15+\sqrt{ 185 }$.
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