Question
Find roots of polynomial $$ p(x) = x^2+2x-600 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 23.5153\\[1 em]x_2 &= -25.5153 \end{aligned} $$Explanation
The solutions of $ x^2+2x-600 = 0 $ are: $ x = -1-\sqrt{ 601 } ~ \text{and} ~ x = -1+\sqrt{ 601 }$.
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