Question
Find roots of polynomial $$ p(x) = x^2+2-3 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1\\[1 em]x_2 &= -1 \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ x^2+ \color{blue}{2} \color{blue}{-3} = x^2 \color{blue}{-1} $$Step 2:
The solutions of $ x^2-1 = 0 $ are: $ x = -1 ~ \text{and} ~ x = 1$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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