Question
Find roots of polynomial $$ p(x) = x^2+14x-49 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2.8995\\[1 em]x_2 &= -16.8995 \end{aligned} $$Explanation
The solutions of $ x^2+14x-49 = 0 $ are: $ x = -7-7 \sqrt{ 2 } ~ \text{and} ~ x = -7+7 \sqrt{ 2 }$.
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