Question
Find roots of polynomial $$ p(x) = x^2+12x+26 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -2.8377\\[1 em]x_2 &= -9.1623 \end{aligned} $$Explanation
The solutions of $ x^2+12x+26 = 0 $ are: $ x = -6-\sqrt{ 10 } ~ \text{and} ~ x = -6+\sqrt{ 10 }$.
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