Question
Find roots of polynomial $$ p(x) = x^2-4x-40 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 8.6332\\[1 em]x_2 &= -4.6332 \end{aligned} $$Explanation
The solutions of $ x^2-4x-40 = 0 $ are: $ x = 2-2 \sqrt{ 11 } ~ \text{and} ~ x = 2+2 \sqrt{ 11 }$.
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