Question
Find roots of polynomial $$ p(x) = x^2-36x+36 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 34.9706\\[1 em]x_2 &= 1.0294 \end{aligned} $$Explanation
The solutions of $ x^2-36x+36 = 0 $ are: $ x = 18-12 \sqrt{ 2 } ~ \text{and} ~ x = 18+12 \sqrt{ 2 }$.
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