Question
Find roots of polynomial $$ p(x) = x^2-16x-377 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 29\\[1 em]x_2 &= -13 \end{aligned} $$Explanation
The solutions of $ x^2-16x-377 = 0 $ are: $ x = -13 ~ \text{and} ~ x = 29$.
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