The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 13.0902\\[1 em]x_2 &= 1.9098 \end{aligned} $$The solutions of $ x^2-15x+25 = 0 $ are: $ x = \dfrac{ 15 }{ 2 }-\dfrac{ 5 \sqrt{ 5}}{ 2 } ~ \text{and} ~ x = \dfrac{ 15 }{ 2 }+\dfrac{ 5 \sqrt{ 5}}{ 2 }$.
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