Question
Find roots of polynomial $$ p(x) = x^2-14x+45 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 9\\[1 em]x_2 &= 5 \end{aligned} $$Explanation
The solutions of $ x^2-14x+45 = 0 $ are: $ x = 5 ~ \text{and} ~ x = 9$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator