Question
Find roots of polynomial $$ p(x) = w^2+2w-64 $$
Answer
The roots of polynomial $ p(w) $ are:
$$ \begin{aligned}w_1 &= 7.0623\\[1 em]w_2 &= -9.0623 \end{aligned} $$Explanation
The solutions of $ w^2+2w-64 = 0 $ are: $ w = -1-\sqrt{ 65 } ~ \text{and} ~ w = -1+\sqrt{ 65 }$.
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