Question
Find roots of polynomial $$ p(x) = v^2-7v-18 $$
Answer
The roots of polynomial $ p(v) $ are:
$$ \begin{aligned}v_1 &= 9\\[1 em]v_2 &= -2 \end{aligned} $$Explanation
The solutions of $ v^2-7v-18 = 0 $ are: $ v = -2 ~ \text{and} ~ v = 9$.
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