The roots of polynomial $ p(t) $ are:
$$ \begin{aligned}t_1 &= 0\\[1 em]t_2 &= 5 \end{aligned} $$Step 1:
Factor out $ \color{blue}{ t }$ from $ t^2-5t $ and solve two separate equations:
$$ \begin{aligned} t^2-5t & = 0\\[1 em] \color{blue}{ t }\cdot ( t-5 ) & = 0 \\[1 em] \color{blue}{ t = 0} ~~ \text{or} ~~ t-5 & = 0 \end{aligned} $$One solution is $ \color{blue}{ t = 0 } $. Use second equation to find the remaining roots.
Step 2:
To find the second zero, solve equation $ t-5 = 0 $
$$ \begin{aligned} t-5 & = 0 \\[1 em] t & = 5 \end{aligned} $$