Question
Find roots of polynomial $$ p(x) = t^2-2t+10 $$
Answer
The roots of polynomial $ p(t) $ are:
$$ \begin{aligned}t_1 &= 1+3i\\[1 em]t_2 &= 1-3i \end{aligned} $$Explanation
The solutions of $ t^2-2t+10 = 0 $ are: $ t = 1+3i ~ \text{and} ~ t = 1-3i$.
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