Question
Find roots of polynomial $$ p(x) = t^2-11t+28 $$
Answer
The roots of polynomial $ p(t) $ are:
$$ \begin{aligned}t_1 &= 7\\[1 em]t_2 &= 4 \end{aligned} $$Explanation
The solutions of $ t^2-11t+28 = 0 $ are: $ t = 4 ~ \text{and} ~ t = 7$.
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