Question
Find roots of polynomial $$ p(x) = s^2+72s+144 $$
Answer
The roots of polynomial $ p(s) $ are:
$$ \begin{aligned}s_1 &= -2.0589\\[1 em]s_2 &= -69.9411 \end{aligned} $$Explanation
The solutions of $ s^2+72s+144 = 0 $ are: $ s = -36-24 \sqrt{ 2 } ~ \text{and} ~ s = -36+24 \sqrt{ 2 }$.
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