Question
Find roots of polynomial $$ p(x) = s^2+2s+10 $$
Answer
The roots of polynomial $ p(s) $ are:
$$ \begin{aligned}s_1 &= -1+3i\\[1 em]s_2 &= -1-3i \end{aligned} $$Explanation
The solutions of $ s^2+2s+10 = 0 $ are: $ s = -1+3i ~ \text{and} ~ s = -1-3i$.
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