Question
Find roots of polynomial $$ p(x) = r^2-2r+26 $$
Answer
The roots of polynomial $ p(r) $ are:
$$ \begin{aligned}r_1 &= 1+5i\\[1 em]r_2 &= 1-5i \end{aligned} $$Explanation
The solutions of $ r^2-2r+26 = 0 $ are: $ r = 1+5i ~ \text{and} ~ r = 1-5i$.
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