Question
Find roots of polynomial $$ p(x) = p^2-2200p $$
Answer
The roots of polynomial $ p(p) $ are:
$$ \begin{aligned}p_1 &= 0\\[1 em]p_2 &= 2200 \end{aligned} $$Explanation
Step 1:
Factor out $ \color{blue}{ p }$ from $ p^2-2200p $ and solve two separate equations:
$$ \begin{aligned} p^2-2200p & = 0\\[1 em] \color{blue}{ p }\cdot ( p-2200 ) & = 0 \\[1 em] \color{blue}{ p = 0} ~~ \text{or} ~~ p-2200 & = 0 \end{aligned} $$One solution is $ \color{blue}{ p = 0 } $. Use second equation to find the remaining roots.
Step 2:
To find the second zero, solve equation $ p-2200 = 0 $
$$ \begin{aligned} p-2200 & = 0 \\[1 em] p & = 2200 \end{aligned} $$This page was created using
Polynomial Roots Calculator