Question
Find roots of polynomial $$ p(x) = m^2-14m+9 $$
Answer
The roots of polynomial $ p(m) $ are:
$$ \begin{aligned}m_1 &= 13.3246\\[1 em]m_2 &= 0.6754 \end{aligned} $$Explanation
The solutions of $ m^2-14m+9 = 0 $ are: $ m = 7-2 \sqrt{ 10 } ~ \text{and} ~ m = 7+2 \sqrt{ 10 }$.
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