Question
Find roots of polynomial $$ p(x) = 9x^2+14x-15 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.7294\\[1 em]x_2 &= -2.285 \end{aligned} $$Explanation
The solutions of $ 9x^2+14x-15 = 0 $ are: $ x = -\dfrac{ 7 }{ 9 }-\dfrac{ 2 \sqrt{ 46}}{ 9 } ~ \text{and} ~ x = -\dfrac{ 7 }{ 9 }+\dfrac{ 2 \sqrt{ 46}}{ 9 }$.
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