Question
Find roots of polynomial $$ p(x) = 9x^2-6x+37 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \dfrac{ 1 }{ 3 }+2i\\[1 em]x_2 &= \dfrac{ 1 }{ 3 }-2i \end{aligned} $$Explanation
The solutions of $ 9x^2-6x+37 = 0 $ are: $ x = \dfrac{ 1 }{ 3 }+2i ~ \text{and} ~ x = \dfrac{ 1 }{ 3 }-2i$.
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