Question
Find roots of polynomial $$ p(x) = 9x^2-14-3 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \dfrac{\sqrt{ 17 }}{ 3 }\\[1 em]x_2 &= - \dfrac{\sqrt{ 17 }}{ 3 } \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ 9x^2 \color{blue}{-14} \color{blue}{-3} = 9x^2 \color{blue}{-17} $$Step 2:
The solutions of $ 9x^2-17 = 0 $ are: $ x = - \dfrac{\sqrt{ 17 }}{ 3 } ~ \text{and} ~ x = \dfrac{\sqrt{ 17 }}{ 3 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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