Question
Find roots of polynomial $$ p(x) = 8x^2+6x-1 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.1404\\[1 em]x_2 &= -0.8904 \end{aligned} $$Explanation
The solutions of $ 8x^2+6x-1 = 0 $ are: $ x = -\dfrac{ 3 }{ 8 }-\dfrac{\sqrt{ 17 }}{ 8 } ~ \text{and} ~ x = -\dfrac{ 3 }{ 8 }+\dfrac{\sqrt{ 17 }}{ 8 }$.
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