Question
Find roots of polynomial $$ p(x) = 8x^2+34-9 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \dfrac{ 5 \sqrt{ 2}}{ 4 }i\\[1 em]x_2 &= -5 \dfrac{\sqrt{ 2 }}{ 4 }i \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ 8x^2+ \color{blue}{34} \color{blue}{-9} = 8x^2+ \color{blue}{25} $$Step 2:
The solutions of $ 8x^2+25 = 0 $ are: $ x = \dfrac{ 5 \sqrt{ 2}}{ 4 } i ~ \text{and} ~ x = -5 \dfrac{\sqrt{ 2 }}{ 4 } i $.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator