Question
Find roots of polynomial $$ p(x) = 7x^2-9x-12 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2.1015\\[1 em]x_2 &= -0.8158 \end{aligned} $$Explanation
The solutions of $ 7x^2-9x-12 = 0 $ are: $ x = \dfrac{ 9 }{ 14 }-\dfrac{\sqrt{ 417 }}{ 14 } ~ \text{and} ~ x = \dfrac{ 9 }{ 14 }+\dfrac{\sqrt{ 417 }}{ 14 }$.
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