Question
Find roots of polynomial $$ p(x) = 7x^2-6x-4 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.2975\\[1 em]x_2 &= -0.4404 \end{aligned} $$Explanation
The solutions of $ 7x^2-6x-4 = 0 $ are: $ x = \dfrac{ 3 }{ 7 }-\dfrac{\sqrt{ 37 }}{ 7 } ~ \text{and} ~ x = \dfrac{ 3 }{ 7 }+\dfrac{\sqrt{ 37 }}{ 7 }$.
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