Question
Find roots of polynomial $$ p(x) = 7n^2+2n+6 $$
Answer
The roots of polynomial $ p(n) $ are:
$$ \begin{aligned}n_1 &= -\dfrac{ 1 }{ 7 }+\dfrac{\sqrt{ 41 }}{ 7 }i\\[1 em]n_2 &= -\dfrac{ 1 }{ 7 }- \dfrac{\sqrt{ 41 }}{ 7 }i \end{aligned} $$Explanation
The solutions of $ 7n^2+2n+6 = 0 $ are: $ n = -\dfrac{ 1 }{ 7 }+\dfrac{\sqrt{ 41 }}{ 7 }i ~ \text{and} ~ n = -\dfrac{ 1 }{ 7 }-\dfrac{\sqrt{ 41 }}{ 7 }i$.
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