Question
Find roots of polynomial $$ p(x) = 6m^2+43m+72 $$
Answer
The roots of polynomial $ p(m) $ are:
$$ \begin{aligned}m_1 &= -\dfrac{ 8 }{ 3 }\\[1 em]m_2 &= -\dfrac{ 9 }{ 2 } \end{aligned} $$Explanation
The solutions of $ 6m^2+43m+72 = 0 $ are: $ m = -\dfrac{ 9 }{ 2 } ~ \text{and} ~ m = -\dfrac{ 8 }{ 3 }$.
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