The roots of polynomial $ p(k) $ are:
$$ \begin{aligned}k_1 &= \dfrac{ 1 }{ 6 }\\[1 em]k_2 &= -1 \end{aligned} $$The solutions of $ 6k^2+5k-1 = 0 $ are: $ k = -1 ~ \text{and} ~ k = \dfrac{ 1 }{ 6 }$.
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