Question
Find roots of polynomial $$ p(x) = 64x+32 $$
Answer
The root of polynomial $ p(x) $ is:
$$ \begin{aligned}x &= -\dfrac{ 1 }{ 2 } \end{aligned} $$Explanation
$$ \begin{aligned} 64x+32 & = 0 \\[1 em]
64 \cdot x & = -32 \\[1 em]
x & = - \frac{ 32 }{ 64 } \\[1 em]
x & = - \frac{ 32 : 32 }{ 64 : 32} \\[1 em]
x & = -\frac{ 1 }{ 2 }
\end{aligned} $$
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