Question
Find roots of polynomial $$ p(x) = 629+400x $$
Answer
The root of polynomial $ p(x) $ is:
$$ \begin{aligned}x &= -\dfrac{ 629 }{ 400 } \end{aligned} $$Explanation
$$ \begin{aligned} 629+400x & = 0 \\[1 em]
400 \cdot x & = -629 \\[1 em]
x & = - \frac{ 629 }{ 400 }
\end{aligned} $$
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