Question
Find roots of polynomial $$ p(x) = 6-7x^2+2x $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.0796\\[1 em]x_2 &= -0.7939 \end{aligned} $$Explanation
Step 1:
Write polynomial in descending order
$$ \begin{aligned} 6-7x^2+2x & = 0\\[1 em] -7x^2+2x+6 & = 0 \end{aligned} $$Step 2:
The solutions of $ -7x^2+2x+6 = 0 $ are: $ x = \dfrac{ 1 }{ 7 }-\dfrac{\sqrt{ 43 }}{ 7 } ~ \text{and} ~ x = \dfrac{ 1 }{ 7 }+\dfrac{\sqrt{ 43 }}{ 7 }$.
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