Question
Find roots of polynomial $$ p(x) = 5s^2+17s+24 $$
Answer
The roots of polynomial $ p(s) $ are:
$$ \begin{aligned}s_1 &= -\dfrac{ 17 }{ 10 }+\dfrac{\sqrt{ 191 }}{ 10 }i\\[1 em]s_2 &= -\dfrac{ 17 }{ 10 }- \dfrac{\sqrt{ 191 }}{ 10 }i \end{aligned} $$Explanation
The solutions of $ 5s^2+17s+24 = 0 $ are: $ s = -\dfrac{ 17 }{ 10 }+\dfrac{\sqrt{ 191 }}{ 10 }i ~ \text{and} ~ s = -\dfrac{ 17 }{ 10 }-\dfrac{\sqrt{ 191 }}{ 10 }i$.
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