Question
Find roots of polynomial $$ p(x) = 56x^2+66x+156 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -\dfrac{ 33 }{ 56 }+\dfrac{\sqrt{ 7647 }}{ 56 }i\\[1 em]x_2 &= -\dfrac{ 33 }{ 56 }- \dfrac{\sqrt{ 7647 }}{ 56 }i \end{aligned} $$Explanation
The solutions of $ 56x^2+66x+156 = 0 $ are: $ x = -\dfrac{ 33 }{ 56 }+\dfrac{\sqrt{ 7647 }}{ 56 }i ~ \text{and} ~ x = -\dfrac{ 33 }{ 56 }-\dfrac{\sqrt{ 7647 }}{ 56 }i$.
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