Question
Find roots of polynomial $$ p(x) = 500x^2-500x+96 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.7408\\[1 em]x_2 &= 0.2592 \end{aligned} $$Explanation
The solutions of $ 500x^2-500x+96 = 0 $ are: $ x = \dfrac{ 1 }{ 2 }-\dfrac{\sqrt{ 145 }}{ 50 } ~ \text{and} ~ x = \dfrac{ 1 }{ 2 }+\dfrac{\sqrt{ 145 }}{ 50 }$.
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