Question
Find roots of polynomial $$ p(x) = 500+505x-50x^2 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 11.0084\\[1 em]x_2 &= -0.9084 \end{aligned} $$Explanation
Step 1:
Write polynomial in descending order
$$ \begin{aligned} 500+505x-50x^2 & = 0\\[1 em] -50x^2+505x+500 & = 0 \end{aligned} $$Step 2:
The solutions of $ -50x^2+505x+500 = 0 $ are: $ x = \dfrac{ 101 }{ 20 }-\dfrac{\sqrt{ 14201 }}{ 20 } ~ \text{and} ~ x = \dfrac{ 101 }{ 20 }+\dfrac{\sqrt{ 14201 }}{ 20 }$.
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