Question
Find roots of polynomial $$ p(x) = 4x^2+29+28x $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -1.2639\\[1 em]x_2 &= -5.7361 \end{aligned} $$Explanation
Step 1:
Write polynomial in descending order
$$ \begin{aligned} 4x^2+29+28x & = 0\\[1 em] 4x^2+28x+29 & = 0 \end{aligned} $$Step 2:
The solutions of $ 4x^2+28x+29 = 0 $ are: $ x = -\dfrac{ 7 }{ 2 }-\sqrt{ 5 } ~ \text{and} ~ x = -\dfrac{ 7 }{ 2 }+\sqrt{ 5 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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