Question
Find roots of polynomial $$ p(x) = 4x^2-16x^2+19x-6 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.1477\\[1 em]x_2 &= 0.4357 \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ \color{blue}{4x^2} \color{blue}{-16x^2} +19x-6 = \color{blue}{-12x^2} +19x-6 $$Step 2:
The solutions of $ -12x^2+19x-6 = 0 $ are: $ x = \dfrac{ 19 }{ 24 }-\dfrac{\sqrt{ 73 }}{ 24 } ~ \text{and} ~ x = \dfrac{ 19 }{ 24 }+\dfrac{\sqrt{ 73 }}{ 24 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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