Question
Find roots of polynomial $$ p(x) = 4s^2+24s-100 $$
Answer
The roots of polynomial $ p(s) $ are:
$$ \begin{aligned}s_1 &= 2.831\\[1 em]s_2 &= -8.831 \end{aligned} $$Explanation
The solutions of $ 4s^2+24s-100 = 0 $ are: $ s = -3-\sqrt{ 34 } ~ \text{and} ~ s = -3+\sqrt{ 34 }$.
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