Question
Find roots of polynomial $$ p(x) = 48x^2+42x-153 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.4007\\[1 em]x_2 &= -2.2757 \end{aligned} $$Explanation
The solutions of $ 48x^2+42x-153 = 0 $ are: $ x = -\dfrac{ 7 }{ 16 }-\dfrac{\sqrt{ 865 }}{ 16 } ~ \text{and} ~ x = -\dfrac{ 7 }{ 16 }+\dfrac{\sqrt{ 865 }}{ 16 }$.
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