Question
Find roots of polynomial $$ p(x) = 47x^2+624x-196 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.307\\[1 em]x_2 &= -13.5836 \end{aligned} $$Explanation
The solutions of $ 47x^2+624x-196 = 0 $ are: $ x = -\dfrac{ 312 }{ 47 }-\dfrac{ 2 \sqrt{ 26639}}{ 47 } ~ \text{and} ~ x = -\dfrac{ 312 }{ 47 }+\dfrac{ 2 \sqrt{ 26639}}{ 47 }$.
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